Question

$\frac{b }{2}$
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Answer 1

Answer:

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Answer 2

Answer:

cos(A +C) = sin B. (1)

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2 2

In a Triangle,

In a Triangle,sum of its angles = 180°

In a Triangle,sum of its angles = 180°therefore, A + B + C = 180°

In a Triangle,sum of its angles = 180°therefore, A + B + C = 180° = A + C = 180 - B. (2)

putting (2) in (1),

cos (180 - B) = sin B

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2 2

=> cos (90 - B) = sin B

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2 2

by complementary angles ;

cos(90 - theta) = sin (theta)

therefore,

sin B = sin B

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2 2

LHS=RHS

Step-by-step explanation:

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