Question

$\frac{b + (b + 1) + (b + 2)}{4} = 21$
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Answer 1

$\huge\star{\tt{\underline{\underline{\red{Answer}}}}}\star$

$\frac{b + (b + 1) + (b + 2)}{4} = 21$

$\implies$ $\frac{b + b + 1+ b + 2}{4} = 21$

$\implies$$\frac{3b + 3 }{4} = 21$

$\implies$3b+3 =21 x 4

$\implies$ 3b= 84-3

$\implies$ b= 81/3

$\implies$ $\large{\boxed{\boxed{b=27}}}$

Answer 2

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

$= > \frac{b + (b + 1) + (b + 2)}{4} = 21$

$= > \frac{b + b + 1 + b + 2}{4} = 21$

$= > \frac{3b + 3}{4} = 21$

$= > 3b + 3 = 21 \times 4$

$= >3b = 84 - 3$

$= > b = \frac{81}{3}$

$= > b = 27$

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$\huge{\underline{\underline{\mathfrak{Thank you}}}}$