Question

$\frac{b + (b + 1) + (b + 2)}{4} = 21$

Answer 1

Here is your answer

$\frac{b + (b + 1) + (b + 2)}{4} = 21 \\ 3b + 3 = 21 \times 4 \\ 3b + 3 = 84 \\ 3b = 84 - 3 \\ 3b = 81 \\ b = \frac{81}{3} \\ b = 27$
Hope it helps you

Answer 2

Hi friends

Answer is

$b + b + 1 + b + 2 = 21 \times 4 \\ 3b = 84 - 3 \\ b = \frac{81}{3} \\ b = 27$
Hope it helps