Question

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ᴾʳᵒᵛᵉ ᵗʰᵃᵗ
$\frac{ \cot(90 - e) \sin(90 - e) }{ \sin(e) } + \frac{ \cot(40) }{ \tan(50) } - ( \cos ^{2} {20} - \cos ^{2} 70 ) = 1$
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Answer 1

Step-by-step explanation:

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