Question

$\frac{n}{3} + 1 = 4 - n \\ solve \: it$

Answer 1

$\huge{\textsf{Answer;}}$


$\frac{n}{3} + 1 = 4 - n \\ \\ \frac{n + 3}{3} = 4 - n \\ \\ \\ n + 3 = 3(4 - n) \\ \\ n + 3 = 12 - 3n \\ \\ \\ 3n + n \: = \: 12 - 3 \\ \\ 4n \: \: = \: 9 \\ \\ n = \frac{9}{4}$

Answer 2

$\underline{\underline{\bold{\red{QUESTION}}}}$ ➡

$\underline{ \bold{To \: \: solve \: : }} \: \: \: \: \boxed {\bold{ \: \: \: \: \frac{n}{3} + 1 = 4 - n \: \: \: }}$





$\underline{\underline{\bold{\red{SOLUTION \: \: WITH \: \: EXPLAINTION}}}}$

$\bold{ \frac{n}{3} + 1 = 4 - n} \\ \\ \bold{ = > \frac{n + 3}{3} = 4 - n \: \: \: \: \: \: \: \: [Taking \: \: 3 \: \: as \: \: L.C.M. \: \: } \\ \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: in \: \: \: L.H.S.]} \\ \\ \\ = > \bold{n + 3 = 3(4 - n)} \\ \\ \bold{ = > n + 3 = 12 - 3n} \\ \\ \bold{ = > n + 3n = 12 - 3} \\ \\ \bold{ = > 4n = 9} \\ \\ = > \bold{n = \frac{9}{4} }$


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$\underline{\underline{\bold{\red{VERIFICATION}}}}$➡

$\bold{Here,} \: \: \: \: \: \: \: \: \: \: \underline{\bold{ \: \: \: n = \frac{9}{4} \: \: \: \: }}\: \\ \\ \\ \bold{Now,} \\ \\ \bold{L.H.S. = \frac{n}{3} + 1 } \\ \\ \bold{ = \frac{ \frac{9}{4} }{3} + 1} \\ \\ \bold{ = \frac{9}{4} \times \frac{1}{3} + 1 } \\ \\ \bold{ = \frac{3}{4} + 1 } \\ \\ \bold{ = \frac{3 + 4}{4} } \\ \\ = \bold{ \frac{7}{4} } \\ \\ \bold{Again,}\\ \\ \bold{R.H.S. =4 - n } \\ \\ \bold{ = 4 - \frac{9}{4} } \\ \\ \bold{ = \frac{16 - 9}{4} } \\ \\ = \bold{ \frac{7}{4} } \\ \\ \bold{So, \: \: \: \: } \: \: \: \: \: \: \: \underline{\underline{\bold{ \: \: \: L.H.S.= R.H.S. \: \: \: }}}$

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$\underline{\underline{\bold{\red{ANSWER}}}}$ ➡ $\boxed{\boxed{ \bold{ \: \: \: n = \: \frac{9}{4} \: \: \: \: }}}$


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✝$\mathfrak{\red{THANKS…}}$✝