Question

$\frac{sec \: + tan \:c }{cosec + cot} = \frac{cosec - cot}{sec \: - tan}$
prove that​

Answer 1

Answer:

let L.H.S=x and R.H.S=y

x/y=(secA+tanA)(secA-tanA)

.......,........................................

(cosecA-cotA)(cosecA+cotA)

=(sec^2 A-tan^2 A)

.................................

(cosec^2 A -cot^2 A)

= 1/1=1

Therefore x/y=1

x=y