Question

$\frac{ \sin(a) \tan(a) }{1 - \cos(a) } = 1 + \sec(a)$
prove​

Answer 1

$\mathfrak{\large{\underline{\underline{Answer:-}}}}$

In this type of question first you have to change tan $\a$

in $\bold{ \frac{sina}{cosa} }$ form then you have to use the suitable identity.

$\bold{ tan \: a \: = \frac{sin \: a}{cos \: a} }$

Identity used :-

$\bold{{ \sin}^{2} a = 1 - {cos}^{2} a }$

Dear!! User kindly refer to attachment.

Answer 2

Answer:

In this type of question first you have to change tan \a\a

in \bold{ \frac{sina}{cosa} }

cosa

sina

form then you have to use the suitable identity.

\bold{ tan \: a \: = \frac{sin \: a}{cos \: a} }tana=

cosa

sina

Identity used :-

\bold{{ \sin}^{2} a = 1 - {cos}^{2} a }sin

2

a=1−cos

2

a

Dear!! User kindly refer to attachment.