Math, asked by piyush2754, 1 year ago


 \frac{sina + cosa}{sina - cosa} +  \frac{sina - cosa}{sina + cosa} =  \frac{2}{ {sin}^{2}a -  {cos}^{2}a}
please solve the problem

Answers

Answered by ayush1293
1
LHS=
 \frac{(sina + cosa)(sina + cosa) + (sina - cosa)(sina - cosa)}{(sina - cosa)(sina + cosa)}
=
 \frac{ {(sina + cosa)}^{2} + ( {sina - cosa)}^{2}  }{ {sin}^{2}a -  {cos}^{2}a }
=
 \frac{ {sin}^{2}a +  {cos}^{2}a + 2sina.cosa +  {sin}^{2}a +  {cos}^{2}a - 2sin.cos    }{ {sin}^{2}a -  {cos}^{2}a  }
=
 \frac{1 + 1}{ {sin}^{2}a -  {cos}^{2}a  }
=
 \frac{2}{ {sin}^{2}a -  {cos}^{2}a  }
LHS=RHS
Similar questions