Question

$\frac{ \sqrt{3} }{ \sqrt{6} + \sqrt{3} }$
rationalise the denominator ​

Answer 1

Answer:

$\frac{ \sqrt{3} }{ \sqrt{6 + \sqrt{3 } } } \times \frac{ \sqrt{6 - \sqrt{3} } }{ \sqrt{6 - \sqrt{3 } } } = \frac{ \sqrt{3( \sqrt{6 - \sqrt{3)} } } }{3}$