Question

$\frac{ - \sqrt{6} + \sqrt{ - 12} }{3} \\ \\ solve \:$
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Answer 1

Step-by-step explanation:

the square root of a negative number does not exist in the set of real numbers

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Answer 2

• combin using the product rule for radical

$\sqrt{6.12}$

• multiple 6 by 12

$\sqrt{72}$

$rewrite 72 \: as \: {6}^{2} .2$

$\sqrt{ {6}^{2} } .2$

• Decimal form.

$8.48528137$

Hope it helps you ✍️

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