Question

$\frac{tan41}{cos49}$
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Answer 1

$\sf\dfrac{tan 41°}{cos 49°}$

= $\sf\dfrac{tan (90-49)°}{cos 49°}$

= $\sf\dfrac{cot 49°}{cos 49°}$

= (cos 49°/sin49°)/cos 49°

= $\bold{\dfrac{1}{sin 49°}}$

Hope Helps uh..! :)

Answer 2

$\frac{ \tan(41) }{ \cos(49) } \\ \frac{ \tan(90 - 49) }{ \cos(49) } \\ \frac{ \cos(49) }{ \cos(49) } \\ \frac{1}{ \sin(49) }$