Question

$\frac{ {x}^{2} + 12 + 7x }{x + 4}$
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Answer 1

Answer:

hope the above attachment helps.

Answer 2

Answer:

$\frac{x {}^{2} + 12 + 7x }{x + 4}$

$\frac{x {}^{2} + 7x + 12 }{x + 4}$

$\frac{x {}^{2} + (4 + 3)x + 12 }{x + 4}$

$\frac{x {}^{2} + 4x + 3x + 12 }{x + 4}$

$\frac{x (x + 4) + 3(x + 4) }{x + 4}$

$\frac{x + 3)(x + 4)}{x + 4}$

$(x + 3) \: \: is \: \: the \: \: answer$