Question

$\frac{x {}^{2} }{32} - \frac{y {}^{2} }{18} \\ \ \\ \frac{2 {x}^{2} }{49} - 162{y}^{2} \\ \\ \frac{9 {p}^{2} }{25} - \frac{ {16q}^{2} }{49} \\ \\ \frac{25}{36} {x}^{2} {y}^{2} - \frac{ {9q}^{2} }{16} {y}^{2} {z}^{2} \\ \\ \frac{ {xy}3{} }{98} - \frac{ {x}3{y} }{32}$
factorise the following expression using a identity
using formula
1.
${a }^{2} + {b }^{2} = {a}^{2} + {b}^{2} + 2ab$
$(a - b) {}^{2} = {a}^{2} + {b}^{2} - 2ab$
$( {a}^{2} - {b}^{2} ) = (a + b)(a - b)$
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Answer 1

Answer:

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