Question

$\frac{x}{2} + \frac{2y}{3} = - 1 \: and \: x - \frac{y}{3} = 3$
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given :

$\frac{x}{2} + \frac{2y}{3} = - 1 \: \: and \: \: \: x - \frac{y}{3 } = 3$

To find :

The value of x and y.

Solution :

Multiplying by 6 and 3 in 1st and 2nd equation respectively, we get,

3x + 4y = -6 - - -(a)

3x - y = 9 - - -(b)

Now, subtracting equation (b) from equation (a) we have,

3x + 4y - (3x - y) = -6-9

=> 4y + y = -15

=> 5y = -15

=> y = -3

Substituting y = - 3 in equation (b) we get,

3x - (-3) = 9

=> 3x + 3 = 9

=> 3x = 9 - 3

=> 3x = 6

=> x = 2.

Hence, x = 2 and y = -3.