Question

$\frac{x}{2} + \frac{y}{3} = 1 \\ \frac{x}{3} + \frac{y}{2} = 11 \\ by \: elimination \: method$
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Answer 1

find the attached photo for the answer

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Answer 2

$\frac{x}{2} +\frac{y}{3}=1\\ \\\frac{3x+2y}{6}=1\\ \\3x+2y=6----(i)$

$\frac{x}{3}+\frac{y}{2}=11\\ \\\frac{2x+3y}{6}=11\\ \\2x+3y=66----(ii)$

Multiplying (i) and (ii) equations by 2 and 3 respectively and then subtracting them we get ;

6x + 4y =    12

6x ± 9y = ±198

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-5y = - 186

y = 37.2

Putting this value in (i) equation ;

3x + 2 ( 37.2 ) = 6

3x + 74.4 = 6

3x = 6 - 74.4

3x = -68.4

x = -22.8

I think u have given wrong equations but I've given the solution. The values of x and y is very different but if u have correct equations u can solve them in a similar way.

Hope it helps u ..  :D