Question

$\frac{x - 2}{x + 19} = \frac{1}{2} \:$
x=?
​

Answer 1

Answer:

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$\large\frac{x - 2}{x + 19} = \frac{1}{2}$

What is the value of x?

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$\large \frak{ \underline{ \underline{ \purple{Solⁿ :}}}}$

$\large = > \frac{x - 2}{x + 19} = \frac{1}{2}$

$\large = > 2(x - 2) = 1(x + 19)$

$\large = > 2x - 4 = x + 19$

$\large = > 2x - x = 19 + 4 = 23$

$\large= > x = 23$

$\large \frak{ \underline{ \underline{ \blue{To \: check \: whether \: solution \: is \: correct \: or \: not :}}}}$

L.H.S

$\large{ = > \frac{23 - 2}{23 + 19} = \frac{ \cancel{21}}{ \cancel{42}} = \frac{1}{2} }$

$\large{= \frac{1}{2} }$

R.H.S

$\large{ = \frac{1}{2} }$

$\large{L.H.S = R.H.S}$

$\large \mathfrak{ \fcolorbox{magenta}{white}{ \color{magenta}{Hence \: proved}}}$

Hope it helps...

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