Question

$\frac{x^{3}}{8} - 64 - 3 {x}^{2} + 24x$
factorise

plz help

I will Mark brainlist

Answer 1

Answer:

$=>{(\frac{x}{2} - 4)^3$

Step-by-step explanation:

$=>Given:\frac{x^3}{8}-64-3x^2+24x$

$=>(\frac{x}{2})^3 - (4)^3 - 3x^2 + 24x$

$=>(\frac{x}{2})^3-(4)^3-3*(\frac{x}{2})^2*4+3*\frac{x}{2}*(4)^2$

It is in the form of a³ - b³ - 3a²b + 3ab² = (a - b)³

$=> \boxed{(\frac{x}{2} - 4)^3}$

Hope it helps!

Answer 2

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