Question

$\frac{x}{3}+\frac{x}{4}+\frac{x}{5}=1$

Answer 1

$⊱ \: \sf{Question}$

$\rm\dfrac{x}{3}+\dfrac{x}{4}+\dfrac{x}{5}=1$

Answer

$= \dfrac{60}{47} = \boxed{\red{1 \dfrac{13}{47}} }$

Solution

In order to solve such equations you have to apply the rule of algebra which states that in order to find the unknown value the foremost step to be taken is to separate the known values on RHS and the rest unknown value on LHS

First take LCM of 3 , 4 & 5 .

$\begin{array}{c|c}2&3,4,5 \\ 2&3,2,5 \\ 3&3,1,5 \\ 5&1,1,5 \\ &1,1,1 \end{array} \\ ↣ \red{2 \times 2 \times 3 \times 5} = \pink{60}$

Now proceed the Calculation :-

$\rm\dfrac{x}{3}+\dfrac{x}{4}+\dfrac{x}{5}=1 \\ \\ = \sf \dfrac{20x + 15x + 12x}{60} = 1 \\ \\ \sf \dfrac{47x}{60} = 1$

$\therefore \sf47x = 60 \\ \boxed{\sf x = \dfrac{60}{47}}$

Therefore, we have calculated the value for x which is 60/47 .

Thankyou