Question

$\frac{x + 32}{x + 6} \leqslant 6 \\ \\ \frac{4}{x} + \frac{1}{ {x}^{2} } = {1}{5 {x}^{2} } \\ \\ 1 + \frac{2}{x + 1} < \frac{2}{x } \\ \\ \\ \frac{3x}{x + 1} = \frac{12}{ {x - 1}^{2} } + 2 \\ \\ \\ \frac{2}{4 {x}^{2} - 9} + \frac{1}{2x - 3} = \frac{3}{2x + 3}$
help po please kailangan kuna ngayon​

Answer 1

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