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Step-by-step explanation:
Given that,
x/5 + y/4 = 4 ⇒ 4x + 5y / 20 = 4 ⇒4x + 5y = 80-----eq ( 1 ) ( say)
x/2 - y/4 = 3 ⇒ 2x - y/4 = 3 ⇒ 2x - y = 12-------eq (2 ) (say)
Now, multiplying eq ( 2 ) by 2 ,we get
2× [ 2x - y = 12 ] ⇒ 4x - 2y = 24-------eq ( 3 ) (say )
On subtracting eq ( 1 ) - eq ( 2 ) , we get
4x + 5y - ( 4x - 2y ) = 80 - 24
4x + 5y - 4x + 2y = 56 (∵ - × + = - ; - × - = + )
7y = 56
y = 56/7 (∵transposing )
y = 8 .
On substituting " y = 8 " in ( 1 ) ,we get
4x + 5 ( 8 ) = 80
4x + 40 = 80
4x = 80 - 40 ( ∵transposing )
4x = 40
x = 40/4 (∵transposing )
x = 10 .
∴The values of x and y are 8 and 10.
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