Question

$\frac{x - \sqrt{6} }{ \sqrt{3} \ + = \sqrt{2} } = 3 \sqrt{3} - 4 \sqrt{2}$


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Answer 1

$\frac{x - \sqrt{6} }{ \sqrt{3} \ + = \sqrt{2} } = 3 \sqrt{3} - 4 \sqrt{2}$