Question

$\frac{x}{y} + \frac{y}{x} = 1 hale \: {x}^{3} + {y}^{3} kata$

Answer 1

Answer :

Given,

x/y + y/x = 1

⇒ (x² + y²)/(xy) = 1

⇒ x² + y² = xy

⇒ x² + y² - xy = 0

⇒ x² - xy + y² = 0 ...(i)

Now, x³ + y³

= (x + y) (x² - xy + y²)

= (x + y) × 0, by (i)

= 0

∴ x³ + y³ = 0

#MarkAsBrainliest

Answer 2

Solution:-

given by :-

》x/y+y/x = 1 , x^3+y^3= ?

》= x^2+y^2 = xy

》= x^2+y^2-xy = 0

now we have

》x^3+y^3 = (x+y)(x^2+y^2-xy)

》= x^3+y^3 = (x+y)×0

》= (x^3 +y^3 = 0)ans