Question

$\frac{x-y}{\sqrt{x}+\sqrt{y} }$

Answer 1

Answer

$\frac{x-y}{\sqrt{x}+\sqrt{y}} \\ \\ = \frac{(x - y)}{(\sqrt{x}+\sqrt{y})} \times \frac{\sqrt{x} - \sqrt{y}}{\sqrt{x} - \sqrt{y}} \\ \\ = \frac{(x - y){(\sqrt{x} - \sqrt{y}})}{ { \sqrt{x} }^{2} - \sqrt{ {y}^{2} } } \\ \\ = \frac{(x - y)(\sqrt{x} - \sqrt{y})}{(x - y)} \\ \\ = \sqrt{x} - \sqrt{y}$