Question

$\frac{y - (4 - 3y)}{2y - (3 + 4y)}$
=1/5​

Answer 1

Answer:

$y=0.1$

Step-by-step explanation:

$\frac{y-(4-3y)}{2y-(3+4y)} = \frac{1}{5}$

$={5[y-(4-3y)}={1[2y-(3+4y)}$ Cross multiply them.

$={5y-(4-3y)=}{2y-(3+4y)}$

$={5y-4+3y}={2y-3-4y}$

$={5y+3y-4}={2y-4y-3}$

$= 8y-4=-2y-3$

$= 8y+2y=4-3$

$=10y=1$

$y=\frac{1}{10}$

$y=0.1$