Question

$\green{Please}$$\pink{Answer }$$\green{The}$$\pink{Question}$​

Answer 1

Answer:

gave any other questions

AB289

nivu kannadigara

Answer 2

Given,

• The Length of a 10cm high cuboid exceeds its breadth by 4 cm.
• If Volume of the Cuboid is 2210 cm³.

To Find,

• Length of Cuboid

Solution :

$\longmapsto$ Suppose the Breadth of Cuboid be a

Therefore, Length will be a + 4 And Height already given - 10 cm

$\bigstar \underline{\pink{\tt{According\:to\:the\:Question :}}}$

$\longrightarrow \boxed{\sf{Volume\:of\:Cuboid = Length \times Breadth \times Height}}$

$\longrightarrow \sf{2210 = (a + 4) \times a \times 10}$

$\longrightarrow \sf{\dfrac{2210}{10} = a^{2} + 4a}$

$\longrightarrow \sf{221 = a^{2} + 4a}$

$\longrightarrow \sf{a^{2} + 4a - 221 = 0}$

$\longrightarrow \sf{a^{2} + 17a -13a - 221 = 0}$

(Spillitary Method Use)

$\longrightarrow \sf{a(a + 17) -13(a + 17) = 0}$

$\longrightarrow \sf{(a - 13) (a + 17) = 0}$

$\longrightarrow \sf{a = 13\:or\:a = -17}$

║Breadth can't be Negative so a ≠ -17║

Therefore,

$\bigstar \boxed{\green{\tt{Breadth\:of\:Cuboid = a = 13\:cm}}}$

$\bigstar \boxed{\green{\mathfrak{Length\:of\:Rectangle = a + 4 = 13+4 = 17\:cm}}}$

$\rule{200}2$