Physics, asked by King412, 2 months ago


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Six point masses each of mass m are placed at the vertices of a regular hexagon of side l. The force acting on any of the masses is:


 \\  \underline{ \large†\color{red}\frak{ \:  \:  Answer  \: With  \: full \:  explanation \:  : }}

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Answered by Anonymous
28

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

Six point masses each of mass m are placed at the vertices of a regular hexagon of side l. The force acting on any of the masses is:

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Refer the attachment given below

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\huge\colorbox{orange}❤\colorbox{indigo}{\red{Thanks}}\colorbox{orange}❤

\huge\colorbox{orange}❤\colorbox{indigo}{\green{from}}\colorbox{orange}❤

\large\red{\underbrace{\overbrace\mathbb{\colorbox{aqua}{\colorbox{blue}{\colorbox{purple}{\colorbox{pink}{\colorbox{green}{\colorbox{gold}{\colorbox{silver}{\textit{\purple{\underline{\red{《❀miss-Jay-Maharashtra✿》࿐}}}}}}}}}}}}}}

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Answered by MizzCupid
3

 \\ \green {\underline {\underline{ \sf \huge{Question :- }}}} \\

Six point masses each of mass m are placed at the vertices of a regular hexagon of side l. The force acting on any of the masses is:

 \\ \green {\underline {\underline{ \sf \huge{Answer:- }}}} \\

in the attachment !

bhot lamba h xD kon likhne jaye ^•^

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