3 and 4
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no report class 9
Answers
Step-by-step explanation:
annyeong!
Answer 3
Diagonals of a square are perpendicular bisectors of each other.
So, angle IMJ=90°
A square has all the 4 angles as right angles.
Also, diagonals of a square bisect the opposite angles.
Answer 4
Let ABCD be the rhombus.
AC = 20 cm and BD = 21 cm
We know that the diagonals of a rhombus bisect at right angles.
SO, AO = OC = 10 cm
And BO = OD = 10.5 cm
Thus, each side of us = 14.5 cm
Perimeter =AB+BC+CD+DA
=14.5+14.5+14.5+14.5
=58 cm .
Answer:
58 cm
Step-by-step explanation:
Answer 3
Diagonals of a square are perpendicular bisectors of each other.
So, angle IMJ=90°
A square has all the 4 angles as right angles.
Also, diagonals of a square bisect the opposite angles.
\begin{gathered} \bf \: So, < JIK= \frac{1}{2} \times 90 \degree =45 \degree \\ \bf \: Similarly , < LJK= \frac{1}{2} \times 90 \degree =45 \degree\end{gathered}
So,<JIK=
2
1
×90°=45°
Similarly,<LJK=
2
1
×90°=45°
\begin{gathered}\begin{gathered} \\ \rule{200pt}{3pt} \end{gathered} \end{gathered}
Answer 4
Let ABCD be the rhombus.
AC = 20 cm and BD = 21 cm
We know that the diagonals of a rhombus bisect at right angles.
SO, AO = OC = 10 cm
And BO = OD = 10.5 cm
\begin{gathered} \bf \: ln \: angle \: triangle \: AOB , \\ A O ^ 2 + O B ^ 2 = A B ^ 2 \\ \bf\Rightarrow10^ 2 +10.5^ 2 =AB^ 2 \\ \bf \: \Rightarrow100+110.25=AB^ 2 \\ \bf \Rightarrow AB^ 2 =210.25 \\ \bf \Rightarrow AB=14.5 cm\end{gathered}
lnangletriangleAOB,
AO
2
+OB
2
=AB
2
⇒10
2
+10.5
2
=AB
2
⇒100+110.25=AB
2
⇒AB
2
=210.25
⇒AB=14.5cm
Thus, each side of us = 14.5 cm
Perimeter =AB+BC+CD+DA
=14.5+14.5+14.5+14.5
=58 cm .
hope it will help you army