Math, asked by sonasg80892, 19 days ago


hello \: army

3 and 4

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no report class 9​

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Answers

Answered by Anonymous
32

Step-by-step explanation:

annyeong!

Answer 3

Diagonals of a square are perpendicular bisectors of each other.

So, angle IMJ=90°

A square has all the 4 angles as right angles.

Also, diagonals of a square bisect the opposite angles.

 \bf \: So, < JIK=  \frac{1}{2}   \times 90 \degree =45 \degree \\ \bf \: Similarly , < LJK=  \frac{1}{2}  \times 90 \degree =45 \degree

\begin{gathered} \\ \rule{200pt}{3pt} \end{gathered}

Answer 4

Let ABCD be the rhombus.

AC = 20 cm and BD = 21 cm

We know that the diagonals of a rhombus bisect at right angles.

SO, AO = OC = 10 cm

And BO = OD = 10.5 cm

 \bf \: ln  \: angle \:  triangle  \: AOB , \\ A O ^ 2 + O B ^ 2 = A B ^ 2 \\  \bf\Rightarrow10^ 2 +10.5^ 2 =AB^ 2 \\ \bf \: \Rightarrow100+110.25=AB^ 2 \\ \bf \Rightarrow AB^ 2 =210.25 \\  \bf \Rightarrow AB=14.5 cm

Thus, each side of us = 14.5 cm

Perimeter =AB+BC+CD+DA

=14.5+14.5+14.5+14.5

=58 cm .

Answered by angelinaangel388
5

Answer:

58 cm

Step-by-step explanation:

Answer 3

Diagonals of a square are perpendicular bisectors of each other.

So, angle IMJ=90°

A square has all the 4 angles as right angles.

Also, diagonals of a square bisect the opposite angles.

\begin{gathered} \bf \: So, < JIK= \frac{1}{2} \times 90 \degree =45 \degree \\ \bf \: Similarly , < LJK= \frac{1}{2} \times 90 \degree =45 \degree\end{gathered}

So,<JIK=

2

1

×90°=45°

Similarly,<LJK=

2

1

×90°=45°

\begin{gathered}\begin{gathered} \\ \rule{200pt}{3pt} \end{gathered} \end{gathered}

Answer 4

Let ABCD be the rhombus.

AC = 20 cm and BD = 21 cm

We know that the diagonals of a rhombus bisect at right angles.

SO, AO = OC = 10 cm

And BO = OD = 10.5 cm

\begin{gathered} \bf \: ln \: angle \: triangle \: AOB , \\ A O ^ 2 + O B ^ 2 = A B ^ 2 \\ \bf\Rightarrow10^ 2 +10.5^ 2 =AB^ 2 \\ \bf \: \Rightarrow100+110.25=AB^ 2 \\ \bf \Rightarrow AB^ 2 =210.25 \\ \bf \Rightarrow AB=14.5 cm\end{gathered}

lnangletriangleAOB,

AO

2

+OB

2

=AB

2

⇒10

2

+10.5

2

=AB

2

⇒100+110.25=AB

2

⇒AB

2

=210.25

⇒AB=14.5cm

Thus, each side of us = 14.5 cm

Perimeter =AB+BC+CD+DA

=14.5+14.5+14.5+14.5

=58 cm .

hope it will help you army

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