Math, asked by dasm212003gmailcom, 1 year ago


 { |hello | | friends}
I need Help in math graph question you have to solve.
I had attached question.
See it.

Graph of Quadratic polynomial

Answer
Should follow steps
Should follow clear answer

Attachments:

Answers

Answered by JinKazama1
7
Steps :
1) We will check this in form of
a {x}^{2} + bx + c
If a > 0 , then graph /Parabola is opening upwards (Part 1 )

If a < 0 , then graph / Parabola is opening downward.

2)
We will check about value of Discriminant,
D = b^2 - 4ac
If D > 0 , then roots are real and distinct
=> Graph cuts the x - axis at two distinct points .
If D = 0 , then roots are equal and real.
=> Graph cuts the axis at only one point.
If D < 0, then roots are imaginary.
So , graph will not cut the x axis.

3) Now, here we will check about vert^x of parabola,
V = ( -b/2a , -D/ 4a)

we will just look at sign of these vertex points.
To see in which side, does the parabola lies.

4) We will see Y-intercept of graph by putting x = 0 in given equation which tells us about
where y - axis is cutted by graph.

For Calculation see Pic.
Attachments:

JinKazama1: See there are four pics
FuturePoet: nice answer
JinKazama1: :)
JinKazama1: I added one more pic 5 graph of first part with g^nerated
FuturePoet: ohhk good i will also answer it soon
neosingh: thanks a lot bro
JinKazama1: :)
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