Question

$hey \: guys \\ here \: is \: ur \: question \:$
*****=*******=******=********=****☺
$(1) \: find \: radius \: and \: diameter \: of \\ \: following \: measurement$
$(a) \: circumference \: \\ (i)35.2cm \\ (ii)22cm$
Solve it.
Genius​

Answer 1

Answer:

hola mate

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Step-by-step explanation:

i)

circumferemence = πd

35.2=22/7x

x=352×7/220

x=11.2

radius is 56cm

ii)

22=22/7x

x=22×7/22

x=7

radius is 3.5cm

#answer with quality

#BAL

Answer 2

Answer:

$\huge{\underline{\underline{Given→}}}$

$\sf\green{Length\:of\:rectangel=x+2\:units}$

$\sf\green{Breadth\:of\:rectangel=2x\:units}$

$\huge{\underline{\underline{To\:Find→}}}$

$\sf\purple{Perimeter\:of\:the\:rectangle}$

$\sf\color{purple}{Area\:of\:the\:rectangle}$

$\huge{\underline{\underline{Answer→}}}$

Perimeter:-

As perimeter =2(Lenght+Breadth)

$\sf\blue{→P=2(l+b)}$

$\sf\blue{→P=2(2x+x+2)}$

$\sf\blue{→P=4x+2x+4}$

$\sf\blue{→P=6x+4}$

$\mathrm{\boxed{\boxed{\pink{→P=6x+4✔}}}}$

Area:-

As area =Length x Breadth

$\sf\color{blue}{→Ar=l\times b}$

$\sf\color{blue}{→Ar=2x\times (x+2)}$

$\sf\color{blue}{→Ar=2x(x+2)}$

$\sf\color{blue}{→Ar=2x^2+4x}$

${\boxed{\boxed{\pink{→Ar=2x^2+4x✔}}}}$

☞ Hence the Perimeter of the rectangle is 6x+4 units and it's area is $\mathrm{2x^2+4x}$ units which is the required answer.

HOPE IT HELPS.