Question

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CALCULATE THE WORK DONE BY A FORCE 30N IN LIFTING LOAD OF 2kg TO A HEIGHT OF 10m ( g = 10ms^2)


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Answer 1

Given :-

Force applied on lifting the load = 30 N

Mass of the load = 2 kg

Height of the load being carried = 10 m

To Find :-

The work done by the force.

Analysis :-

Here we are given with the force, mass and the height.

In order to find the work done substitute the given values from the questions accordingly such that work done is equal to force multiplied by displacement.

Solution :-

We know that,

• m = Mass
• w = Work done
• g = Gravity
• f = Force
• h = Height

Using the formula,

$\underline{\boxed{\sf Work \ done=Force \times Displacement}}$

Given that,

Gravitational force (f) = 30 N

Displacement (s) = 10 m

Substituting their values,

⇒ w = fs

⇒ w = 30 × 10

⇒ w = 300 J

Therefore, the work done by the force is 300 J.

Answer 2

$\Huge\underline{\overline{\mid{\green{Answer}}\mid}}$

hey guy here is your answer

as we know that w = displacement × force

so, here

work done =

force = 30N

displacement = 10m

so put i into formula then you will get

300 j

$\Huge \boxed{ \colorbox{gold}{hope \: this \: helps}}$