Math, asked by meenakumari74988, 9 months ago


hey \: plz \: solve \: this  \\ it \:is \: chapter \: \: rationalisation

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Answered by rajk7489416gmailcom
3

given \\  \\   = \frac{b {}^{2} }{ \sqrt{a {}^{2}  + b {}^{2} } + a }  \:  \\ \\  \boxed{ \green{step \: by \: step \: explanation}} \\  \\  =  \frac{b {}^{2} }{ \sqrt{a {}^{2}  + b {}^{2} }  + a}  \times \:  \frac{ \sqrt{a {}^{2} + b {}^{2}  } - a  }{ \sqrt{a {}^{2}  + b {}^{2} }  - a }  \\   \\ =  \frac{b {}^{2} ( \sqrt{a {}^{2}  + b {}^{2} } - a )}{a {}^{2}  + b { }^{2}  - a}

Answered by AaravpandeyAV1306
3

Step-by-step explanation:

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