Question

$how \: much \: does \: x {}^{2} - 2 \alpha x + 5 \: exceed \: 3x ^{2} - 5x + 6$
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Answer 1

Required solution

$\small \bold{=3x^2 −5x+6−(x^2−2ax+5)}$

$\bold{=2x^2−(5+2a)x+1}$

∴$\bold{x^2−2ax+5}$ exceeds $\bold {3x^2−5x+6}$ by $\bold {2x^2−(5+2a)x+1}$