Question

$how \: much \: larger \: is \: 11x3 - 5x { }^{2} + 3 \: than \: 6x3 + 7x$
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Answer 1

Answer:

(11x³ - 5x² + 3) is (5x³ - 5x² - 7x + 3) more than (6x³ + 7x).

Step-by-step explanation:

We have, 11x³ - 5x² + 3 and 6x³ + 7x

and we must find how much is 11x³ - 5x² + 3 is larger than 6x³ + 7x.

To find that, we must subtract them,

So,

(11x³ - 5x² + 3) - (6x³ + 7x)

Opening the brackets,

11x³ - 5x² + 3 - 6x³ - 7x

11x³ - 6x³ - 5x² - 7x + 3

5x³ - 5x² - 7x + 3

Hence,

11x³ - 5x² + 3 is (5x³ - 5x² - 7x + 3) more than 6x³ + 7x.

Hope it helped and believing you understood it........All the best