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According to Law of reciprocal Proportion , the ratio of the weights of any two elements X and Y which combines with a fixed weight of third element Z and that is either the same Or some simple multiple of the ratio of weights in which X and Y combines with each other.
Let there be two elements C ( carbon ) and O ( oxygen ) combine separately with third element H ( hydrogen ) to form the compound and and they combine directly with each other to form
Now in this , If we take our ratio of the compounds formed by weight we will get the ratio » OR
This ratio is of
In Ratio will be same i.e 12 : 32 OR 3:8 which is same as of first ratio.
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RiyaSharma01:
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Answer:
Here's my explanation.
Explanation:
The law of reciprocal proportions states that, "If two different elements combine separately with a fixed mass of a third element, the ratio of the masses in which they do so are either the same as or a simple multiple of the ratio of the masses in which they combine with each other".
Although this law may seem complicated, it is fairly easy to understand with an example.
For example, 3 g of C react with 1 g of H to form methane.
Also, 8 g of O react with 1 g of H to form water.
The mass ratio of C:O=3:8.
In the same way, 12 g of C react with 32 g of Oto form CO2.
The mass ratio of C:O = 12:32 = 3:8.
The mass ratio in which C and O combine with each other is the same as the mass ratio in which they separately combine with a fixed mass of H.
Similarly, 12 g of C react with 16 g of O to form CO.
Here, the mass ratio of C:O = 12:16 = 3:4.
The mass ratio in which they separately react with a fixed mass of H is 3:8.
The ratio of the two ratios is 3/43/8=84=21.
Here, the ratio in which C and O combine with each other is twice the ratio in which they separately combine with a fixed mass of H.
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