Question

tex]\huge\bf{\colorbox{gold}{\color{red}{QUESTION}}}[/tex]
$\large\tt{The~equation}~\dfrac{x²}{10-a}~\large{+}\dfrac{y²}{4-a}~\large=1~represents~an~ellipse,if$
$\tt{1)~a<4}$
$\tt{2)~a>4}$
$\tt{3)~4<a<10}$
$\tt{4)~a>0}$​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

tex]\huge\bf{\colorbox{gold}{\color{red}{QUESTION}}}[/tex]

\large\tt{The~equation}~\dfrac{x²}{10-a}~\large{+}\dfrac{y²}{4-a}~\large=1~represents~an~ellipse,ifThe equation

10−a

x²

+

4−a

y²

=1 represents an ellipse,if

\tt{1)~a < 4}1) a<4

\tt{2)~a > 4}2) a>4

\tt{3)~4 < a < 10}3) 4<a<10

\tt{4)~a > 0}4) a>0