Question

$\huge \bf{Equation : - }$

$: \implies \sf \bigg( \dfrac{60}{16} - x \bigg) - \bigg(\dfrac{60}{16} + x\bigg) = 2$

Check the given equation.
Find the value of x and Verify also the answer..

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Answer 1

★Solution:-

$: \implies \sf \bigg( \dfrac{60}{16} - x \bigg) - \bigg(\dfrac{60}{16} + x\bigg) = 2 \\ \\ \\ :\implies \bigg( \frac{60}{16 - x} \bigg) - \bigg( \frac{60}{16 + x } \bigg) \\ \ \\ \ : \implies60(16 + x) - 60(16 - x) \\ = 2(16 + x)(16 - x) \\ \\ :\implies60(16 + x - 16 + x) \\ = 2(16 {}^{2} - {x}^{2} ) \\ \\ :\implies \: 30(2x) = {16}^{2} - {x}^{2} \\ \\ : \implies \: 60x = 256 - {x}^{2} \\ \\ : \implies \: {x}^{2} + 60x - 256 = 0 \\ \\: \implies {x}^{2} + 64x - 4x - 256 = 0 \\ \\ :\implies \: x(x + 64) - 4(x + 64) = 0 \\ \\ :\implies \: (x + 64)(x - 4) = 0 \\ \\ :\implies \: x = 4 \:, - 64$