Question

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Can Any solve this question
The questions I have marked.



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Answer 1

Answer:

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Step-by-step explanation:

B(i)

see image

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B(iv)

Multiple of 3 between 1 to 15 are 3 6 9 12 15

Total number = 5

Total number of tickets = 15

Probability that a ticket drawn at random is a multiple of 3 = 5/15 = 1/3

Answer 2

Answer:

Given, A.P = 8, 13, 18, 23...

Here, a = 8; d = 5 and n = 13

\implies⟹ Now,

\implies⟹ a_{n} = a + (n - 1)da

n

=a+(n−1)d

\implies⟹ a_{13} = 8 + (13 - 1)5a

13

=8+(13−1)5

\implies⟹ a_{13} = 8 + (12)5a

13

=8+(12)5

\implies⟹ a_{13} = 8 + 60a

13

=8+60

\implies⟹ a_{13} = 68a

13

=68

Hence, the 13th term of the given A.P is 68.