Question

$\huge\bf\green{Question}$

The image of an object placed 16cm away from a concave mirror forms at distance of 24 cm from the mirror.Calculate the possible focal lengths of the concave mirror from the information.​

Answer 1

$\huge\green\star{~\underline{\red{\textsf {\textbf{An}\blue{\textbf {\textsf{sw}}\pink{\textbf{\textsf{er}}}\orange{\textsf{\textbf{~:-}}}}}}}}$

The Question Does not mention that weather The image formed After or before the mirror

So,v = (+ - 24)

Now,

$\: \: \: \: \: \: \: :\implies \sf \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}$

$\: \: \: \: \: \: \: :\implies \sf \dfrac{1}{ - 24} + \dfrac{1}{ - 16}$

$\: \: \: \: \: \: \: :\implies \sf \dfrac{- 1}{9.6}$

F = 9.6cm

Now With v = (+24)

$\: \: \: \: \: \: \: :\implies \sf \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}$

$\: \: \: \: \: \: \: :\implies \sf \dfrac{1}{ 24} + \dfrac{1}{ - 16}$

$\: \: \: \: \: \: \: :\implies \sf \dfrac{ - 1}{48}$

F = 48cm

$\large \boxed {\tt{ \red{Hence, F = 9.6cm, or \: 48cm}}}</p><p>$

Answer 2

Answer:

v = (+ - 24)

Now,

\: \: \: \: \: \: \: :\implies \sf \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}:⟹

f

1

=

v

1

+

u

1

\: \: \: \: \: \: \: :\implies \sf \dfrac{1}{ - 24} + \dfrac{1}{ - 16}:⟹

−24

1

+

−16

1

\: \: \: \: \: \: \: :\implies \sf \dfrac{- 1}{9.6}:⟹

9.6

−1

F = 9.6cm

Now With v = (+24)

\: \: \: \: \: \: \: :\implies \sf \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}:⟹

f

1

=

v

1

+

u

1

\: \: \: \: \: \: \: :\implies \sf \dfrac{1}{ 24} + \dfrac{1}{ - 16}:⟹

24

1

+

−16

1

\: \: \: \: \: \: \: :\implies \sf \dfrac{ - 1}{48}:⟹

48

−1

F = 48cm

\large \boxed {\tt{ \red{Hence, F = 9.6cm, or \: 48cm}}} < /p > < p >

Hence,F=9.6cm,or48cm

chrome ma log in ni horha :'(sham ko krugi