● A hammer of mass 500g, moving at 50ms‐¹, strikes a nail. The nail stops the hammer in a very short time of 0.01s. What is the force of the nail on the hammer.
▪︎Note:-
Wrong answer will reported on spot..!!!
Answers
Topic
Impulse
Given
A hammer of mass 500g, moving at 50m/s strikes a nail. The nail stops the hammer in a very short time of 0.01s.
To Find
What is the force of the nail on the hammer ?
Concept Used
Impulse
The total impact by a force within a duration is known as Impulse.
Formula
Impulse = Force × Time
Impulse = Change in Momentum
Force × Time = m∆v
Solution
It is given that
Mass of Hammer, m = 500 g
Mass of Hammer, m = 0.5 kg
Initial velocity of Hammer, u = 50 m/s
Final velocity of Hammer, v = 0 m/s
( as hammer stops after striking )
The nail stops in time = 0.01 s
Apply formula,
Force × Time = m( v - u )
Force × 0.01 = (0.5)( 0 - 50 )
Force = 100 × ( - 25 )
Force = -2500 N
So, force of nail on hammer is -2500 N.
Negative sign shows the direction of Force, so magnitude of Force will be 2500 N.
Answer
So, force of nail on hammer is 2500 N ( in magnitude ).
Note :
Another method could be like shown below,
F = ma
F = m( v - u) / t
Put the values and value will be -2500 N again.
Taking magnitude answer will be 2500 N.
- Mass of Hammer = 500g = 0.5 kg
- Initial Velocity = 50 m/s
- Final velocity = 0 m/s
- Time taken = 0.01 sec
- Force of the nail on the hammer.
Here we have to first find Accleration of the hammer and by applying the formula of Force we will get the Force required.
● Acceleration of the Hammer is :-
● So, Force required is :-
So, Force of the nail on the hammer is -2500 N.