Question

${\huge {\bf {Question⤵}}}$

Calculate the heat produced when 96000 C of charge is transferred in 3 hours through a p.d of 50 volts.

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Answer 1

${\huge {\underbrace {\bf {Question}}}}$

Calculate the heat produced when 96000 C of charge is transferred in 3 hours through a p.d of 50 volts.

Given:-

• Charge (Q) = 96000 C

• Potential difference = 50 volts

• Time = 3 hours

To Find:-

• Calculate the heat produced

Solution:-

We Know that,

${\boxed {\pink {\sf {I={\frac {Q}{t}}}}}}$

Where,

• I is current

• Q is charge

• t is time

${\sf {\implies {I={\frac {Q}{t}}}}}$

$\large {\sf {\implies {I={\frac {96000C}{3\: hours}}}}}$

$\large {\sf {\implies {I={\frac {96000}{3×60×60}}}}}$

${\boxed {\green {\sf {\implies {I=8.89\: A}}}}}$

We also know that,

${\boxed {\pink {\sf {R={\frac {V}{I}}}}}}$

Where,

• R is resistance

• V is Potential difference

• I is current

${\sf {\implies {R={\frac {V}{I}}}}}$

$\large {\sf {\implies {R={\frac {50}{8.89}}}}}$

${\boxed {\green {\sf {\implies {R=5.62 Ω}}}}}$

Heat produced,

${\boxed {\pink {\sf {H={I}^{2}Rt}}}}$

${\sf {\implies {H={8.89}^{2}×5.62×3×60×60}}}$

${\sf {\implies {H=4796932.34J}}}$

${\boxed {\green {\sf {H=4796.932kJ}}}}$

Answer 2

${\huge {\bf {Question}}}$

Calculate the heat produced when 96000 C of charge is transferred in 3 hours through a p.d of 50 volts.

${\huge {\bf {Solution}}}$

Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V. Therefore, the heat generated is 4.8 x 106 J.