Show that, the roots of the equation:-
(p²-q)x²+5(p+q)x-2(p-q) = 0
are real and distinct
class :- 10th
chapter :- quadratic equations
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Nature of the quadratic equation is depend on the discriminant where discriminant =b²-4ac
a=(p-q)
b=5(p+q)
c=-2(p-q)
b²-4ac=[5(p+a)]²+8(p-q)(p-a)
b²-4ac=25p²+25q²+50pq+8p²+8q²-16pq
b²-4ac=33p²+33q²+34pq >0
Therefore roots are real and positive
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Nature of the quadratic equation is depend on the discriminant where discriminant =b²-4ac
a=(p-q)
b=5(p+q)
c=-2(p-q)
b²-4ac=[5(p+a)]²+8(p-q)(p-a)
b²-4ac=25p²+25q²+50pq+8p²+8q²-16pq
b²-4ac=33p²+33q²+34pq >0
Therefore roots are real and positive
861 viewsView 4 Upvoters
Sponsored by HDFC Life
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