Question

${ \huge {\bf {\red {\underline {\underline {Question}}}}}}$
A Ferrari Enzo is able to reach a speed of 134 miles per hour (60 meter/sec) from 0mph in 11 seconds. Assuming constant acceleration, how far would the Enzo travel in this amount of time?
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Answer 1

Given:-

• Initial velocity ,u = 0m/s

• Final velocity ,v = 60m/s

• Time taken ,t = 11 s

To Find:-

• Distance Covered by the Enzo ,s

Solution:-

Firstly we calculate the acceleration of the Ferrari Enzo . Using 1st Equation of Motion

• v = u +at

Where ,

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Substitute the value we get

➨ 60 = 0 + a×11

➨ a = 60/11

➨ a = 5.45m/s²

Acceleration of the Enzo is 5.45 m/s².

Now, using 3rd Equation of motion

• v² = u² +2as

Substitute the value we get

➨ 60² = 0² + 2×5.45 ×s

➨ 3600 = 0 + 10.9 ×s

➨ 3600 = 10.9 ×s

➨ s = 3600/10.9

➨ s = 330 .27 m

Therefore, the distance covered by the Ferrari Enzo is 330 . 27 Metres.

Answer 2

♣GIVEN :–

• Initial velocity (u) = 0 m/s

• Final velocity (v) = 60 m/s

• Time taken (t) = 11 sec

♣TO FIND :–

• Distance travelled by the Enzo (s) = ?

♣SOLUTION :–

➊ First let us find the acceleration of the Enzo using first equation of motion :—

• v = u + at

→ 60 = 0 + (a × 11)

→ 60 = 0 + 11a

→ 60 - 0 = 11a

→ 60 = 11a

→ 11a = 60

→ a = 60/11

➠ a = 5.45 m/s²

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➋ Now we can find the distance covered by the Enzo using the third equation of motion :—

• v² = u² + 2as

→ 60² = 0² + (2 × 5.45 × s)

→ 3600 = 0 + 10.9s

→ 10.9s = 3600

→ s = 3600/10.9

➠ s = 330.27 m

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♣ANSWERS :–

• The Enzo will travel 330.27 m in 11 seconds