Question

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In how many ways the 26 letters of the English alphabet can permuted so that none of the word SUN , TEA , BOY or GIRL occurs ?
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Answer 1

Explanation:

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for TEA and GIRL, N(BD) = 21! for BOY and GIRL, N(CD) = 21! Total number of permutations possible with 26 alphabets where SUN, TEA and BOY occurs always, N(ABC) = (26 - 3 - 3 - 3 + 3)! = 20!

Answer 2

ANSWER:-

17

Total number of permutations possible with 26 alphabets where SUN, TEA, BOY and GIRL occurs always, N(ABCD) = (26 - 3 - 3 - 3 - 4 + 4)! = 17!

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