Question

$\huge\bf\underline\red{Hola}\:!!!$

Priya has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ₹ 55 per m².​

Answer 1

$\large{ \rm { \underline{ \underline{ \red S \pink{O} \purple{LU} \orange{T} \blue{IO} \green{N:-}}}}}$

The given plot is a square with the side 25 m.

$\bm{ \therefore{ \purple{Area \: of \: the \: plot =}}}$

$\rm{ \small{ \blue{25 \times 25 = 625 \: {m}^{2}}}}$

The constructed portion i.e., House is a rectangle having length 20 m and breadth 15 m.

$\bm{ \therefore{ \purple{Area \: of \: the \: house = }}}$

$\rm{ \small{ \blue{20 \times 15 = 300 \: {m}^{2}}}}$

☃️So in this question by using formula we find out area of square and area of rectangle. Let's find out the area of remaining portion i.e garden. To find the area of remaining portion, we will subtract area of square plot from the area of rectangular house.

$\purple{ \small{ \bm{ \therefore{ \purple{Area \: of \: garden =}{ \blue {Area \: of \: plot - Area \: of \: house}}}}}}$

${ \rm{ \small{ \blue{ = 625 \: {m}^{2} - 300 \: {m}^{2}}}}}$

$\rm{ \small{ \blue{ = 325 \: {m}^{2} }}}$

Now,

$\purple{ \small{ \bm{ \purple{Cost \: of \: developing \: 1 \: {m}^{2} \: garden}{ \rm{\blue{ = Rs. \: 55}}}}}}$

$\small{ \bm{ \purple{Cost \: of \: developing \: 325 \: {m}^{2} \: garden = { \rm{ \blue{Rs. \: 325 \times 55}}}}}}$

$\small{ \rm{ \blue{ = Rs. \: 17,875}}}$

$\pink{ \tt{ \therefore{Total \: cost \: of \: developing \: the \: garden = }}}$

$\boxed{\pink{Rs. \: 17,875 }}$

Answer 2

Answer:

The given plot is a square with the side 25 m.

\bm{ \therefore{ \purple{Area \: of \: the \: plot =}}}∴Areaoftheplot=

\rm{ \small{ \blue{25 \times 25 = 625 \: {m}^{2}}}}25×25=625m

2

The constructed portion i.e., House is a rectangle having length 20 m and breadth 15 m.

\bm{ \therefore{ \purple{Area \: of \: the \: house = }}}∴Areaofthehouse=

\rm{ \small{ \blue{20 \times 15 = 300 \: {m}^{2}}}}20×15=300m

2

☃️So in this question by using formula we find out area of square and area of rectangle. Let's find out the area of remaining portion i.e garden. To find the area of remaining portion, we will subtract area of square plot from the area of rectangular house.

\purple{ \small{ \bm{ \therefore{ \purple{Area \: of \: garden =}{ \blue {Area \: of \: plot - Area \: of \: house}}}}}}∴Areaofgarden=Areaofplot−Areaofhouse

{ \rm{ \small{ \blue{ = 625 \: {m}^{2} - 300 \: {m}^{2}}}}}=625m

2

−300m

2

\rm{ \small{ \blue{ = 325 \: {m}^{2} }}}=325m

2

Now,

\purple{ \small{ \bm{ \purple{Cost \: of \: developing \: 1 \: {m}^{2} \: garden}{ \rm{\blue{ = Rs. \: 55}}}}}}Costofdeveloping1m

2

garden=Rs.55

\small{ \bm{ \purple{Cost \: of \: developing \: 325 \: {m}^{2} \: garden = { \rm{ \blue{Rs. \: 325 \times 55}}}}}}Costofdeveloping325m

2

garden=Rs.325×55

\small{ \rm{ \blue{ = Rs. \: 17,875}}}=Rs.17,875

\pink{ \tt{ \therefore{Total \: cost \: of \: developing \: the \: garden = }}}∴Totalcostofdevelopingthegarden=

\boxed{\pink{Rs. \: 17,875 }}

Rs.17,875