Question

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A taxi is travelling at 15 m/s. Its driver accelerates with acceleration 3 m/s2 for 4 s. What is its new velocity?

Please answer correctly
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Answer 1

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Initial Velocity (u) = 15 m/s

Acceleration (a) = 3 m/s²

Time Interval (t) = 4 sec

We have to find Final Velocity :-

Use formula :-

$\large \implies{ \boxed{ \boxed{ \green{ \tt{a \; = \frac{v \ ; \; u}{t}}}}}}$

Let final velocity be "v"

(Putting Values)

⇒ 3 = 15 - v/4

⇒ 3 * 4 = 15 - v

⇒ 12 = 15 - v

⇒ 12 - 15 = -v

⇒ -3 = -v

⇒ v  = 3

Final Velocity (v)=3‐¹

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Answer 2

Answer:

• Hence, the new velocity of taxi is 27 m/s .