Question

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(y + $\dfrac{1}{y}$) = 3 then the value of (y² + $\dfrac{1}{{y}^{2}}$) is

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Answer 1

Answer:

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Answer 2

Answer:

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$value \: of \: ( {y}^{2} + \frac{1}{ {y}^{2} } ) = \: square \: of \: (y + \frac{1}{y} ) \\ \\ = ( {y}^{2} + \frac{1}{ {y}^{2} } ) = {3}^{2} = 9$