Question

$\huge\bigstar\underline\mathfrak{No\:Spam}$​

Answer 1

FORMULA USED

the question is little bit of wrong there should be -14 on the rhs side of the 2nd equation(given above)

now for a pair of linear equations

$ax + by + c = 0 \\ px + qy + r = 0$

the equations will have a infinitely many solutions if the condition is satisfied,given below

$\frac{a}{p} = \frac{b}{q} = \frac{c}{r}$

now the given equations are

$hx + 3y + 7 = 0 \\ 2x + 6y + 14 = 0$

therefore applying the above coditions

$\frac{h}{2} = \frac{3}{6} = \frac{7}{ 14} \\ h = 1 \: \: \: \: (answer)$