Question

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Solve the following system of linear equations by substitution method:

(1) 2x – y = 2

(2) x + 3y =15​

Answer 1

Answer:

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Here, 2x – y = 2

⟹ y = 2x – 2

⟹ x + 3y = 15

Substituting the value of y from (i) in (ii), we get

x + 6x – 6 = 15

⟹ 7x = 21

⟹ x = 3

From (i), y = 2 × 3 – 2 = 4

∴ x = 3 and y = 4

Answer 2

Answer:

$\huge\blue{\boxed{\sf <em>Answ</em><em>er</em><em> </em>}}$

1)

$2x – y = 2 \\ = 2x=2+y \\ = 2x=y+2 \\ = \frac{2x}{2}=\frac{y+2}{2} \\ = </p><p>x=\frac{y+2}{2} \\ = x=\frac{y}{2}+1$

2)

$x + 3y =15 \\ = 3y=15-x \\ = \frac{3y}{3}=\frac{15-x}{3} \\ =y=\frac{15-x}{3} \\ = y=-\frac{x}{3}+5$