An observer 1.2m tall is 28.2m away from the tree . The angle of elevation of the top of the tree from his eye is 600 . What is the height of the tree .
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question :-
An observer 1.2m tall is 28.2m away from the tree . The angle of elevation of the
top of the tree from his eye is 600 . What is the height of the tree
given :-
angle of elevation - 600°
distance - 28.2m
height of observer - 1.2
formula :-
tan D = side opposite to angle D/side adjacent to angle D
solution :-
→tan D = side opposite to angle D/side adjacent to angle D
→ tan D = AE/DE
→ tan 600° = AE/DE
→ 1 = AE/28.2
→ 1 × 28.2 = AE
now,
→ AB = AE + BE
→ AB = 28.2 + 1.2
→ AB = 29.4
therefore
height of the tree is 29.4m
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