The angle of elevation of a plane from a point A on the ground is 60° . After a flight of 30 seconds the angle of elevation changes to 30° . If the plane is flying at a constant height of 3600√3m , find the speed of the plane .
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Answers
question :-
The angle of elevation of a plane from a point A on the ground is 60° . After a flight of 30 seconds the angle of elevation changes to 30° . If the plane is flying at a constant height of 3600√3m , find the speed of the plane .
solution :-
→ tan 60° = AD/CD
→ CD = AD/ tan 60°
substituting AD = 3600√3 and tan 60 = 3 we get
→ CD = 3600√3/√3
→ CD = 3600
in triangle BCE at angle C we get
→ tan 30 = BE/CE
→ CE = BE/tan 30
→ CD + DE = BE / tan 30
substituting BE = 3600 √3 and tan 30 = 1/√3
CD = 3600 and DE = 30s we get
3600 + 30s = 3600√3/1/√3
→ 30s = (3600 × √3 × √3) - 3600
→ 30s = 3600 (3 - 1)
→ s = 120(2)
→ s = 240m/s
therefore the speed of the plane is 240m/s
The angle of elevation of a plane from a point A on the ground is 60° . After a flight of 30 seconds the angle of elevation changes to 30° . If the plane is flying at a constant height of 3600√3m , find the speed of the plane .